Divida o número 20 em partes inversamente proporcionais a 2 e 3

K/2 + k/3 = 20 ===> *(6) mmc
3k + 2k = 120
5k = 120
k = 120/5 = 24

A= k/2 = 24/2 = 12 ✓
B= k/3 = 24/3 = 8 ✓

A+b+c = 205
a/(1/2)+b/3+c/(3/5) = ...

1/2 + 3/1 + 3/5 = (mmc de 2 e 5 = 10)
5/10 + 30/10 + 6/10

fazemos --> a/5 + b/30 + c/6 = (a+b+c)/(5+30+6) = 205/41 = 5
a/5 = 5 --> a = 5*5 --> a = 25
b/30 = 5 --> b = 30*5 --> b = 150
c/6 = 5 --> c = 6*5 --> c = 30

Boa noite

1/2 + 3 + 3/5 = 5/10 + 30/10 + 6/10 = 41/10

k = 205/41 = 5

as partes

p1 = 5k = 5*5 = 25
p2 = 30k = 30*5 = 150
p3 = 6k = 6*5 = 30 

resolução!

x/2 + x/4 + x/6 = 220 MMC = 12

6x + 3x + 2x = 2640

11x = 2640

X = 2640 / 11

X = 240

x/2 => 240/2 = 120x/4 => 240/4 = 60x/6 => 240/6 = 40